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Showing posts with label ramanujan. Show all posts
Showing posts with label ramanujan. Show all posts

Wednesday, October 2, 2024

Why Different Infinities Are Really Equal

ABSTRACT:

Assuming different infinities are unequal leads to strange and counter-intuitive mathematical results such as Ramanujan's finite solutions to infinite divergent series. On the flip side, assuming different infinities are equal leads to infinite solutions to divergent infinite series. This last assumption, however, flies in the face of the current dogma: that different infinities are unequal. This paper offers proofs that show that different infinities are in fact equal.

Cantor's diagonal argument is used to prove that bijection fails between the set of non-negative integers (Z) and the set of real numbers (R). Even though both sets have an infinite number of members, the number of members of Z are not considered equal to the number of members of R. However, the implicit assumption is that infinities behave like finite numbers. If we assume infinity has no upper limit, or fixed value, Cantor's diagonal argument can be turned on its head.

In the diagrams below, we have the diagonal argument:

The top diagram is a list of real numbers paired with non-negative integers to the left. At the bottom diagram, the numbers along the diagonal are changed (in red). This creates a real number that is not on the list. We place that number in red below the list.

As you can see, we started with a list of infinite real numbers, so allegedly there are no positive integers beyond infinity we can assign to this new real number. Thus this new real number is considered uncountable. In fact, real numbers are considered uncountable because they are a continuum, and not discrete, but Cantor's diagonal process shows a way to count real numbers discretely, because if it is repeated, it produces one real number at a time. We can just simply add each newly produced real number to the total. But does this imply that R's infinity is greater than N's? Let's assume, arguendo, this is true. We can then justify counting the new real number with a so-called larger infinity, so we pair it with infinity + 1.

Now, assuming infinity has no upper limit, is infinity + 1 really larger than infinity? Equations 1 through 5 below prove that different infinities are equal.

We can easily show that infinity = infinity + 1, but if that's true, then infinity + 1 = infinity + 2 ... and so on all the way up to infinity^infinity and beyond. Every time we create a new real number, we are adding 1 to infinity which gives us back infinity. Using the diagonal method, we can create a new real number as many times as we like, to a point where we imagine a value greater than infinity. Given that infinity has no upper bound, it should be sufficient to cover any set with infinite members. New members can be added to a an infinite-member set and infinity should still be large enough to cover all the members.

Now here's the rub: if different infinities are equal, why do two lines appear to be unequal? Below, line n and line k each have an infinite number of points; yet, line n is longer than line k. Surely there are more points along line n than line k; albeit, the proof beneath the lines tells a different story:

At 12 we see that an infinite number of zero-points (0 * infinity) can equal either line n or line k. However, at 16 we see that infinity equals n * infinity equals k * infinity. This means that each point along n can be mapped to a unique point along k. This seems incredulous, so let's further test our conclusion. Consider the divergent infinite geometric series below. We derive two different infinities: s and sx. Let's assume they are unequal.

At 23 we end up with an inequality. Infinity simply does not equal a finite number! Albeit, Ramanujan would disagree. As a side note, we can see how Ramanujan got finite solutions to divergent series. He treated different infinities as though they were unequal. Now, watch what happens when we assume different infinities are equal (s = sx):

At 29 we get infinity like we should. This result adds further support to the conclusion that different infinities are equal. Based on what we know so far, the following two equations seem valid:

References:

1. Cantor, Georg. Grundlagen einer allgemeinen Mannigfaltigkeitslehre (Foundations of a General Theory of Sets). jamesrmeyer.com.

2. Cantor, Georg. Uber eine elemtare Frage de Mannigfaltigketslehre (On an Elementary Question of Set Theory). jamesmeyer.com. 3. Cantor's Theorem. Wikipedia

4. 2020. SP20:Lecture 9 Diagonalization. courses.cs.cornell.edu

5. Cantor's Diagonal Argument. Wikipedia

6. Cardinality of the Continuum. Wikipedia

7. Continuum Hypothesis. Wikipedia

Thursday, September 26, 2024

Debunking Ramanujan's Finite Solutions to Divergent Series

ABSTRACT:

This paper shows how an infinite series yields both an infinite solution and a finite solution and how to determine which one is correct and which one is just plain crazy!

Imagine the following geometric series:

Is s convergent or divergent? Does it blow up to infinity or have a finite value? So far, we can't say. However, according to Ramanujan and his apologists, even if s is divergent, it has a finite value. Let's see if this is really the case. With a little algebra we derive equation 5 below:

What solutions will work for equation 5? Here are two:

One solution is infinity. If k is finite, the other solution is finite. This means, if we want, we can always extract a finite solution from a divergent series. It also means we can always extract an infinite solution from a convergent series! Ramanujan claimed that divergent series have finite solutions. He could have (but didn't) claim that convergent series have infinite solutions. If such claims seem counter-intuitive and just plain crazy, it's because they are. Extracting finite solutions from divergent series (or infinity from convergent series) violates the geometric series rules. Here are the rules:

At 9 we have a system of equations that show that the value of x matters. We don't just get to choose willy-nilly which equation we like best. If we choose the appropriate equation for a convergent series, we get a finite solution as we should. If we choose the appropriate equation for a divergent series, we get infinity as we should when x is greater than or equal to 1. Albeit, our system of equations doesn't cover x when it is equal to or less than -1. Let's start with the case where x equals -1:

Equation 10 doesn't converge, nor does it blow up to infinity. The partial sums oscillate between 1 and 0 forever. Mathematical physicists like to take the average of .5. However, it is obvious there are two solutions: 1 and 0. In the case where x is less than -1, the partial sums oscillate toward infinity and minus infinity. Again, there are two solutions. For negative numbers less than or equal to -1 we need two equations:

The complete system of equations is as follows:

Where x is less than or equal to -1, we can take advantage of a peculiar property of infinity: Infinity minus infinity doesn't have to equal zero, since infinity equals any number plus infinity:

Thus when x is less than -1 we can take the average of the two solutions s1 and s2 and get a finite solution. In fact, since n can be any finite number, there can be an infinite number of finite solutions.

Where x equals -1, there is one finite solution: .5.

Now, given what we know about infinity, finite numbers and the geometric series rules, what kind of solution(s) can we extract from the following series:

This is a tricky one, since there is no x variable to tell us which equation to use. So let's go with the usual method. We first take the average of the "a" series:

Then we do some fancy Ramanujan algebra to get the average of the "b" series:

Now that we have the b-series average, we can find solutions to the c-series:

At 38 and 39 above, we have two solutions: infinity and -1/12. One solution seems correct and the other seems counter-intuitive. Are they both valid? There is a test: simply sum up the series. The fastest way to do that is find the average number in the series, then multiply it by the number of terms. The average number and the number of terms are both infinity:

As expected, c = infinity. For any series, a good rule of thumb is if the series is divergent, a finite solution is invalid and just plain crazy! We can tell if a series equals infinity by looking at the last term. If the last term is infinite, then the series sum is infinite because infinity plus a bunch of other numbers equals infinity. We get a finite solution because the series itself does not know if it is convergent or divergent. Both convergent and divergent series are structured the same way: a sum of numbers--so the algebra is the same for both and yields more than one solution. Thus it is up to us to take a further step and test each solution.