Here is my new and improved derivation of Christoffel symbols and the covariant derivative. We begin with the metric. Let's convert the rank-one tensors (xixj) to x^2 and pull it out of the radical:
Next, let's take the ordinary derivative, using the product rule and chain rule of calculus:
In the last equation above, we divided both sides of the equation by (gij)^.5. Below we use identities and substitutions to put the equation into a covariant derivative format, which includes the Christoffel symbol:
Finally, we use a similar process to derive the covariant derivative and Christoffel symbol for a contra-variant metric tensor and co-variant rank-one tensor. These tensors are the inverse of the tensors we worked with above (co-variant metric tensor and contra-variant rank-one tensor).
This is very clear and not too difficult to understand step by step. Well done.
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